Salesforce JavaScript-Developer-I Exam Sample Questions | Latest JavaScript-Developer-I Study Notes
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Salesforce JavaScript-Developer-I certification exam is designed to test the knowledge and expertise of JavaScript developers who work with Salesforce. Salesforce Certified JavaScript Developer (JS-Dev-101) certification is highly valuable for professionals looking to advance their career in the Salesforce ecosystem. JavaScript-Developer-I Exam covers a wide range of topics related to JavaScript and Salesforce including Apex, Visualforce, Lightning Components, and more.
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Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q93-Q98):
NEW QUESTION # 93
Refer to the code below:
Which replacement for the conditionalstatement on line 02 allows a developer to correctly determine that a specific element, myElement on the page had been clicked?
Answer:
Explanation:
event.target.id =='myElement'
NEW QUESTION # 94
Refer to the code below:
Let car1 = new Promise((_ , reject) =>
setTimeout(reject, 2000, "car 1 crashed in" =>
Let car2 =new Promise(resolve => setTimeout(resolve, 1500, "car 2 completed") Let car3 =new Promise(resolve => setTimeout(resolve, 3000, "car 3 completed") Promise.race(( car1, car2, car3))
.then (value => (
Let result = '$(value) the race.';)}
.catch(arr => {
console.log("Race is cancelled.", err);
});
What is the value of result when Promise.race executes?
Answer: D
NEW QUESTION # 95
Which option is true about the strict mode in imported modules?
Answer: D
NEW QUESTION # 96
Refer to the code below:
01 let sayHello = () = > {
02 console.log( ' Hello, World! ' );
03 };
Which code executes sayHello once , two minutes from now?
Answer: A
Explanation:
To schedule a function for later execution in JavaScript, the standard built-in method is:
setTimeout(functionReference, delayInMilliseconds)
Characteristics of setTimeout():
* Executes only once .
* Delay is specified in milliseconds.
* Requires passing the function reference , not calling the function.
Two minutes is:
2 minutes = 120 seconds = 120,000 milliseconds
Now evaluate each option:
Option A: delay(sayHello, 120000);
Incorrect.
There is no built-in delay() function in JavaScript.
Option B: setTimeout(sayHello, 120000);
Correct.
sayHello is passed as a function reference , so it will execute once after 120,000 ms.
Option C: setTimeout(sayHello(), 120000);
Incorrect.
sayHello() calls the function immediately , and the return value (undefined) is passed to setTimeout.
This executes the function right away instead of after two minutes.
Option D: setInterval(sayHello, 120000);
Incorrect.
setInterval() repeats execution every 120,000 ms.
The question requires executing the function once , so this cannot be correct.
JavaScript Knowledge References (text-only)
* setTimeout() schedules a function to run once after a specified delay.
* Passing functionName gives a reference; passing functionName() invokes it immediately.
* setInterval() repeats indefinitely, unlike setTimeout().
NEW QUESTION # 97
A developer writes the code below to return a message to a user attempting to register a new username. If the username is available, a variable named msg is declared and assigned a value on line 03.
function getAvailabilityMessage(item) {
if (getAvailability(item)) {
var msg = " Username available " ;
return msg;
}
}
Answer: B
Explanation:
The correct answer is C .
When getAvailability(item) returns true, the code inside the if block executes:
var msg = " Username available " ;
return msg;
The variable msg receives the string value:
" Username available "
Then that same value is returned from the function.
The key point is that var is function-scoped, not block-scoped. So msg belongs to the function scope of getAvailabilityMessage(). However, because the return msg; statement is inside the same if block, the function immediately returns the assigned string when the username is available.
Option A is incorrect because msg is defined before it is returned.
Option B is incorrect because " newUserName " is not assigned or returned anywhere in the function.
Option D would only happen if getAvailability(item) returned false, because then the function would finish without an explicit return value.
For the available username scenario, the verified answer is C .
NEW QUESTION # 98
......
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